(X^2)+15x=24

Solution for (X^2)+15x=24 equation:

(X^2)+15X=24

We move all terms to the left:

(X^2)+15X-(24)=0

a = 1; b = 15; c = -24;
Δ = b2-4ac
Δ = 152-4·1·(-24)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{321}}{2*1}=\frac{-15-\sqrt{321}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{321}}{2*1}=\frac{-15+\sqrt{321}}{2}
$